split string into chars, for each char get ordinal number, and create string using 8bit  format of the number. Concat all

def str_2_binrep(s):
  return "".join(['{0:008b}'.format(ord(c)) for c in list(s)])

example:

>>> str_2_binrep("Hello World")
'0100100001100101011011000110110001101111001000000101011101101111011100100110110001100100'

If you want to have a space in between, just write

'{0:008b} '

instead.

split string into groups of n characters

fill array with substrings, range(start, stop, stepwidth)

def str_splitintogroups(s, n):
  return [s[i : (i+n) ] for i in range(0, len(s), n)]

example:

>>> str_splitintogroups("split string into groups", 3)
['spl', 'it ', 'str', 'ing', ' in', 'to ', 'gro', 'ups']

XOR of two strings

zip builds tuples containing the ith char of each string; for each pair the xor of the octal number of the char is converted into char and appended

def str_xor(s1, s2):
  return "".join([chr( ord(c1) ^ ord(c2) ) for (c1,c2) in zip(s1, s2)])

example:

>>> str_xor("Hello", "World")
'\x1f\n\x1e\x00\x0b'

>>> str_xor("Hello", "Hello")
'\x00\x00\x00\x00\x00'

Encode String as hex, and decode back

String encode, see http://docs.python.org/2/library/codecs.html#standard-encodings for possible encodings (python 2); output is using 2 digits each per byte of input

example:

>>> "BibiBlocksberg".encode('hex')
'42696269426c6f636b7362657267'

>>> "BibiBlocksberg".encode('hex').decode('hex')
'BibiBlocksberg'

Dec to Hex, Hex to Dec

How to convert a decimal number into a hex representation:

examples:

>>> hex(1000)
'0x3e8'

>>> "%X"%1000
'3E8'

How to convert a from hex (or other) back to decimal representation:

examples:

>>> int("3E8", 16)
1000

>>> int("1001", 2)
9